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<\/figure>\n\n\n\nFoton hem par\u00e7ac\u0131k hem dalgac\u0131k fonksiyonunu protondan \nald\u0131\u011f\u0131 frekanslar \u00fcretir. Bu alanda matematiksel hesaplar\u0131n \nolu\u015fturdu\u011fu bir varsay\u0131m havuzu bulunur deneyden daha \u00e7ok bir matematik \ni\u015fleminin nedenini yorumlayarak ortaya at\u0131lan d\u00fc\u015f\u00fcnceler bulunur. Bu \nvarsay\u0131mlara g\u00f6re \u0131\u015f\u0131k protondan h\u0131z alm\u0131yor k\u00fctle al\u0131yor ve enerjiyi \nelektron kendisi \u00e7evreden ekliyor. N\u00f6tron da h\u0131z\u0131 vermiyor ama \nelektronun foton h\u0131z\u0131n\u0131 karanl\u0131k maddeden ald\u0131\u011f\u0131 sonucuna var\u0131yorlar.<\/p>\n\n\n\n
\n Proton atom par\u00e7alar\u0131 aras\u0131ndan dengesi en zay\u0131f olan par\u00e7a. I\u015f\u0131k ise \nzaten enerji ve k\u00fctleyle atomlara \u00e7arp\u0131yor. Tam bu noktada atomun \nkararl\u0131 durumu \u00f6nem kazan\u0131yor. <\/p>\n\n\n\n
I\u015f\u0131k h\u0131zla gelip atom \u00e7ekirde\u011fine\n \u00e7arpt\u0131\u011f\u0131nda protonun dengesini az az bozar. Bu bozma protonu par\u00e7alamaz\n sadece zaten enerji kayna\u011f\u0131 olan proton daha fazla enerji ile dolunca \ndaha g\u00fc\u00e7l\u00fc hale gelir ve atom par\u00e7alar\u0131 manyetik olarak daha bir birine \nba\u011fl\u0131 hale gelir. Bu ba\u011f \u00e7ekirde\u011fin sal\u0131n\u0131m\u0131n\u0131 farkl\u0131 \u015fekilde de\u011fi\u015ftirir\n ve \u00e7ekirdek elektron avc\u0131l\u0131\u011f\u0131na ba\u015flar. \u00c7ekirdek etraf\u0131nda d\u00f6nem \nelektronlar da frekans de\u011fi\u015fimi nedeniyle dengeli d\u00f6n\u00fc\u015f yapamaz. Atom ya\n elektron alacakt\u0131r yada elektron verecektir.<\/p>\n\n\n\n
Atom bu gibi \ndurumlarda genelde elektron avlar. Ama elektron olmayan durumlarda \nproton dengesini kaybettikce elektron kaybeder. Elektron kaybettikce \natom proton ve n\u00f6tron fazlal\u0131\u011f\u0131 nedeniyle birli\u011fini de kaybeder. Bu \n\u0131\u015f\u0131\u011f\u0131n olu\u015fturdu\u011fu bir par\u00e7alamad\u0131r d\u00fc\u015f\u00fck radyasyon \u00fcretir. \u00c7\u00fcnk\u00fc enerji\n \u00e7evre atomlar taraf\u0131ndan emilir. <\/p>\n\n\n\n
N\u00fckleer bomba da atom \npar\u00e7alanmas\u0131 y\u00fcksek \u0131s\u0131 nedeniyle ortaya \u00e7\u0131kar\u0131l\u0131r ve \u0131s\u0131 yo\u011fun \nalternatif frekans olu\u015fumuna ayr\u0131ca n\u00f6tron ve protonun frekans \nbunal\u0131m\u0131na neden olur. Burada \u00e7ekirdek par\u00e7alan\u0131r ve bu par\u00e7alanmayla \nalfa beta gama gibi radyoaktif par\u00e7ac\u0131klar meydana gelir.<\/p>\n\n\n\n
I\u015f\u0131\u011f\u0131n \nyapt\u0131\u011f\u0131 par\u00e7alama kararl\u0131 atom \u00fcretimine kadard\u0131r. Karbon kararl\u0131 atom \nyap\u0131s\u0131 g\u00f6sterir ama kararl\u0131 de\u011fildir ancak atom yap\u0131s\u0131 \u0131\u015f\u0131\u011f\u0131n protonu \nbesleme \u015feklini de\u011fi\u015ftirir ve protonun g\u00fc\u00e7 dengesi bu atomda \nelektronlarca tekrar sa\u011flan\u0131r. <\/p>\n\n\n\n
Karbon denge kaybederse \u00e7evre atomlarla k\u00fcmele\u015fme i\u00e7ine girer. Karbon atomunun k\u00fcmele\u015fmesi \u0131s\u0131 da da meydana gelir. <\/p>\n\n\n\n
\n I\u015f\u0131\u011f\u0131n maddelere etkisi uzay bo\u015flu\u011funda daha farkl\u0131d\u0131r. I\u015f\u0131k uzayda \natoma hem k\u00fctle hem enerji kazand\u0131r\u0131rken atomun hareket h\u0131z\u0131n\u0131 da \nart\u0131r\u0131r. I\u015f\u0131kla \u00e7arp\u0131\u015fan atom daha da h\u0131zlanacakt\u0131r. G\u00fcne\u015f yelkeni \nd\u00fc\u015f\u00fcncesi de bundan kaynaklan\u0131r.<\/p>\n\n\n\n
I\u015f\u0131\u011f\u0131n maddeleri bozmas\u0131n\u0131 basit\n dille anlatmaya \u00e7al\u0131\u015ft\u0131m. Bozon gravate gibi kavramlar\u0131 kullanmadan \nanlatt\u0131\u011f\u0131m yaz\u0131y\u0131 umar\u0131m be\u011fenirsiniz<\/p>\n","protected":false},"excerpt":{"rendered":"
I\u015f\u0131k s\u0131f\u0131ra yak\u0131n k\u00fctleye sahiptir. I\u015f\u0131\u011f\u0131n k\u00fctlesi oldu\u011funu olduk\u00e7a hassas bir denge terazisi ile anlayabiliyoruz. Bildi\u011fimiz d\u00fcz \u0131\u015f\u0131k – foton elektron taraf\u0131ndan olu\u015fturulur. Elektron \u00e7ekirdek…<\/p>\n","protected":false},"author":1,"featured_media":207,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[57,58,10],"tags":[59,60,61,12],"_links":{"self":[{"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/posts\/206"}],"collection":[{"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/comments?post=206"}],"version-history":[{"count":1,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/posts\/206\/revisions"}],"predecessor-version":[{"id":208,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/posts\/206\/revisions\/208"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/media\/207"}],"wp:attachment":[{"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/media?parent=206"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/categories?post=206"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/robipc.net\/index.php\/wp-json\/wp\/v2\/tags?post=206"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}